A ball of mass M and speed v collides head-on? - one piece v.2 msn
A ball of mass m and velocity v strikes the head
with a ball of mass 2m and speed v / 2, as shown
above. If both balls glued together, their speed
after collision
(A) 0
(B) V / 2
(C)
2
2 v
(D)
2
3 v
(E) 3 V / 2
Two objects of mass 0.2 kilograms, 0.1 kilograms,
, Each in parallel with the x-axis, as
above. The goal reached 0.2 kilograms
collides with the target of 0.1 kilograms. Immediately
after the collision, and the component of the
kg 0,2 is the subject of 1 m / s upward.
What is the Y component of the velocity
0.1 kilograms object immediately after the collision?
(A) 2 m / s downward
(B) 0.5 m / s downward
(C) 0 m / s
(D) 0.5 m / s upward
(E) 2 m / s upward
A stationary object explodes in burglary
three pieces of the masses m, m, and 3M. Both
Pieces of mass m is moving at right angles
the other with the same degree of
mV pulse, as in the picture shown above.
What are the magnitude and direction
Speed3M has a body part?
Thursday, January 28, 2010
One Piece V.2 Msn A Ball Of Mass M And Speed V Collides Head-on?
1 comment:
Well, if the objects are aligned to each other:
M --- V ---> \\ \\ \\ \\ \\ \\ \\ \\ u0026lt ;---- v/2---2M
We know from the conservation of momentum:
M1 m1v1 + m2v2 = (+ M2) v (If sticking)
Mv + 2M (V / 2) = (2m + M) vf
Mv + MV = (M 2 m) VF
2mV = (M 2 m) VF
vf = (2 / 3) v What is DI think?
Well, since you can not see, image type, it is difficult, but I guess who is 0 m / s, and it seems that both the horizontal axis.
Well, if you go in the X direction and one direction, then you have:
mv x) + MV (y () = 3mV (x) + 3 mV (y)
V (x) + v (y) = 3 V (x) + 3v (y)
V (x) = 3 V (x)
v (y) = 3 V (y)
Thus, the X and components and is 1/3v same and therefore the main hall to fly at an angle of 157.25 degrees with one of the two other particles.
(I hope the next time you try to do it later, not only to your work)
-Riley
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